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Posted

I have attempted to play A Golden Opportunity but cannot win this scenario. In fact, I can't get past the Villain's first turn (they have initiative) as I can always replace 2 computer tokens with 2 computer miniatures every single time, and sometimes 3 computers before the Heroes even get a turn. The rules indicate that once there are 2 or more computer miniatures on the map, the game is over. On the Villain's first turn, all 3 Guards can get to three different terminals on their move and then get a chance to complete a Complex Manipulation which they always seem to succeed on at least 2. Deathstroke moves next and almost always activates the Complex Manipulation on his turn as well. By then, at least 2 to 3 computer tokens have been transformed into Computer miniatures. The Villains usually have a couple of energy cubes left after their turn as well, even if I provide them with the maximum re-rolls of 4 in the cube used section. What am I doing wrong??? Are the dice just lucky? Am I interpreting the rules incorrectly?? Do the Heroes get to complete their turn?? Any help, interpretation, etc. would really help. Thank you in advance for any help.

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Posted

I believe you got at least 1 thing wrong.

 

A-Victory conditions:

 

If, at any point, there is only 1 Computer (token or miniature) remaining on the Map, the game ends and the Heroes win.
They have destroyed the door-opening system and prevented the Villain from accessing the vault!

 

Otherwise, the game ends after the Heroes’ turn in round 6:
-THE VILLAIN WINS if there are 2 or more Computer miniatures on the Map. The door-opening system triggers, the Villain gains access to the vault and sends the formula to Lex Luthor.
-THE HEROES WIN if there is 1 or fewer Computer miniatures on the Map. The door-opening system does not trigger and the Villain is unable to access the vault.

 

So even if the villain succeeds in activating all computer tokens on turn 1 (and replacing them with minis), which is not easy (see below), the turn limit is 6.

In all cases, the heroes have 6 turns to destroy the system (i.e. remove 3 computer tokens/minis with a complex thought Difficulty 4).

 

B-Manipulation / Thought.

Security guards do not have a Manipulation stat, they have a Thought stat.

In this scenario, the only villain dudes that have Manipulation are Deathstroke (1 black die) and the Prisonners (1 white + 1 yellow rerollable).

They need 2+4 = 6 cubes to be activated on turn 1 (so 4 cubes left).

It's doable, but chances are the Villain won't be able to succeed all 4 manipulations Difficulty 3 without spending several extra cubes for paid rerolls.

So he'll probably be "half-naked" for the next turn. And the positions of his dudes on the map will probably not be optimal.

 

Posted

Thanks Roolz. That makes more sense. I changed over to a different scenario which was similar and watched a play through video by Paul on line and the rules seemed to explain what you stated a lot easier. Cheers!!

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